Python Program for Leap year

We add a Leap Day on February 29, almost every four years. The leap day is an extra, or intercalary day and we add it to the shortest month of the year, February.
In the Gregorian calendar three criteria must be taken into account to identify leap years:

• The year can be evenly divided by 4, is a leap year, unless:
  • The year can be evenly divided by 100, it is NOT a leap year, unless:
    • The year is also evenly divisible by 400. Then it is a leap year.

This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years

Task
You are given the year, and you have to write a function to check if the year is leap or not.

Note that you have to complete the function and remaining code is given as template.

Output Format

Output is taken care of by the template. Your function must return a boolean value (True/False)

Sample Input  : 1990

Sample output : False

program : 

def is_leap(year):

    if year%4 ==0 and year%100 != 0:

        return True

    elif year%400 ==0:

        return True

    elif year%100 == 0:

        return False

    else:

        return False

year = int(input())

print(is_leap(year))